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Unions aggregate negotiations, wages, and therefore aggregate production time lines. The resulting economy of scale has two results, first much better efficiency because all production can be precomputed. It also has amazing instability when everyone, in phase time, decides to restructure.
Unless they're regulated. Think of utilities.
Unions are often as interested in number of union positions as in salaries. Union members are also often the first to complain about labor saving devices or about having a member do more than one specific job.
Also you assume that there is an option. In many fields, if you aren't a union shop, you can not be in the business (for example, in Hollywood). In this fashion, the unions drive a monopoly reduction in productivity industry-wide.
And the union shops do basically go out of business - but in terms of strikes first before going under.
... Unless they have monopoly power, in which case there aren't other companies with non-union workers to compete away the inefficiency. But I'm not sure there are any private-sector union monopolies any more, so in practice I think you're right.
What you predict in your comments appear to be what is happening in the automotive industry. Capital has been substituted for labor (slowly due to agreements witht he unions). The union causes a price floor for wages in the industry that is slightly less than the union wages but the automotive jobs are being created in non-union states where they build cars with higher quality and probably higher productivity. But the labor force is moving both overseas and to non-union states. The unions (or
their companies) are paying too much and reducing employment (buyouts anyone?). There is still a large auto manufacturing employment base in the US just not in the union states.
Unfortunately, the least secure jobs are often union jobs. If you lose an above market wage job it will not be replaced by a similarly compensated position. It is a difficult position to be in for both the union member and the company they work for.